Get distance to object Irrlicht.

[Justei]

Well, I know this is a very simple task, however I thought someone may find it usefull xD...

Code: Select all

 
         float x,z, dx, dz, distance;
         x = selectedSceneNode->getPosition().X;
         z = selectedSceneNode->getPosition().Z;
 
         dx = (camera->getPosition().X > x) ? camera->getPosition().X - x : x - camera->getPosition().X;
         dz = (camera->getPosition().Z > z) ? camera->getPosition().Z - z : z - camera->getPosition().Z;
 
         cout << "Distance: " << sqrt (dx + dz) << endl;
 

Obviously this is only for distance with x and z, didnt need Y in my case so yeah... xD

[RdR]

Code: Select all

 
f32 distance = node->getAbsolutePosition().getDistanceFrom(camera->getAbsolutePosition());
 

http://irrlicht.sourceforge.net/docu/cl ... 127c3005e2

Should use getAbsolutePosition() else you might get problems when the nodes dont have the same parent.

[Justei]

Huh, googled fast for a function like it but I needed my own anyway so I just made it ^^ but that's really neat lol. Oh well at least I got some more practice xD.

Edit: About getabsoluteposition, I actually don't have the same parent on my nodes and it seems to work fine ^^. But you are most likely right so I'll go for that thx for the tip

[mongoose7]

No point in taking the square root as you didn't square the components (Pythagoras). Just depends what you need.

[hybrid]

I move this away from code snippets, just to avoid people skipping over the rest and implementing these functions always on their own...