example:
Code: Select all
// Copyright (C) 2001-2003
// William E. Kempf
//
// Distributed under the Boost Software License, Version 1.0. (See accompanying
// file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt)
#include <boost/thread/mutex.hpp>
#include <boost/thread/thread.hpp>
#include <iostream>
boost::mutex io_mutex; // The iostreams are not guaranteed to be thread-safe!
class counter
{
public:
counter() : count(0) { }
int increment() {
boost::mutex::scoped_lock scoped_lock(mutex);
return ++count;
}
private:
boost::mutex mutex;
int count;
};
counter c;
void change_count()
{
int i = c.increment();
boost::mutex::scoped_lock scoped_lock(io_mutex);
std::cout << "count == " << i << std::endl;
}
int main(int, char*[])
{
const int num_threads = 4;
boost::thread_group thrds;
for (int i=0; i < num_threads; ++i)
thrds.create_thread(&change_count);
thrds.join_all();
return 0;
}
Also, since I'm planning to use a 2nd thread for network code I am not quite sure where and how to lock/share data between the network thread and irrlicht's main thread.
Let's say the network class in thread 2 receives a new position for an existing unit. This unit, represented by a typical irrlicht related class, has a position member. So, how do I get the received position into the unit class without any problems? Or is there already a general problem because Irrlicht itself is not what's called "thread-safe"?